檢查三個值的等式優雅

[g == b == b == b == c會導致語法錯誤，有其他方法可以確定三個值是否等於。方法This solution is straightforward and efficient, making comparisons on a per-pair basis.

if a == b && a == c {
    fmt.Println("All 3 are equal")
}

With Arrays:

Arrays are comparable, allowing us to compare multiple elements at once:

if [2]interface{}{a, b} == [2]interface{}{b, c} { fmt.println（“所有3個都相等”） }

With Anonymous Structs:

if len(map[interface{}]int{a: 0, b: 0, c: 0}) == 1 {
    fmt.Println("All 3 are equal")
}

if struct{ a, b interface{} }{a, b} == struct{ a, b interface{} } {b，c} { fmt.println（“所有3個都相等”） } ，帶有slices：

if反思 fmt.println（“所有3個都相等”） }

if [2]interface{}{a, b} == [2]interface{}{b, c} {
    fmt.Println("All 3 are equal")
}