）處理多個文件輸入時，通常需要處理多個文件上傳時，通常是必要的。 The

fd.append("fileToUpload[]", files[x]);

Initial Attempt

In JavaScript, a common approach is:

echo 'Name: ' . $_FILES['fileToUpload']['name'][$i] . '<br/>';

However, this code only handles the first selected file.

Solution: Iterating Through Files

To enable multiple file uploads, you need to iterate through all the selected文件：

文件[x]）;

服務器端處理（PHP）

，您可以處理類似的多個文件：
for ($i = 0; $i
echo 'Name: ' . $ _files ['Filetoupload'] ['name'] [$ i]。 '';