Returning Arrays from Functions in C

Attempting to return arrays from functions in C can lead to unexpected behavior, as illustrated by the following code snippet:

int* uni(int *a,int *b)
{
    int c[10];
    ...
    return c;
}

This function attempts to return a local array c from the function. However, when the function returns, the memory occupied by the array is deallocated, resulting in undefined behavior when the caller tries to access it.

The underlying issue lies in the way arrays are stored on the stack. When an array is declared within a function, it is allocated on the stack, a memory region used for local variables and function calls. When the function exits, the memory on the stack is deallocated, including the array's memory.

To resolve this issue, several alternatives exist:

Passing Pointers:

One approach is to pass pointers to the arrays from the main function:

int* uni(int *a,int *b)
{
    ...
    return a;
}

This approach allows the main function to access and manipulate the array directly. However, it requires careful memory management to avoid segmentation faults.

Using Vectors or Arrays:

Instead of using plain arrays, consider utilizing C containers like std::vector or std::array. These containers handle memory management automatically, eliminating the need for manual pointer manipulation.

Returning a Struct:

Another option is to wrap the array within a struct and return the struct instance:

struct myArray
{
   int array[10];
};

myArray uni(int *a,int *b)
{
    ...
    return c;
}

By returning a value (the struct instance), the array's contents are copied into the main function's scope, ensuring their accessibility.